Why is it good to match receiver bandwidth to the bandwidth of the operating mode?
The correct answer is D: It results in the best signal-to-noise ratio. Why it is good to match receiver bandwidth to the bandwidth of the operating mode is that it results in the best signal-to-noise ratio. Matching bandwidth minimizes noise while passing the signal, optimizing SNR. For amateur radio operators, this improves reception. Understanding this helps when operating different modes.
Exam Tip
Match receiver bandwidth to mode = results in best signal-to-noise ratio. Think 'M'atch 'B'andwidth = 'M'inimizes 'B'ackground noise. Matching bandwidth minimizes noise while passing signal, optimizing SNR. Not FCC requirement, not power consumption, not impedance matching - just best SNR.
Memory Aid
"Match receiver bandwidth to mode = results in best signal-to-noise ratio. Think 'M'atch 'B'andwidth = 'M'inimizes 'B'ackground noise. Matching bandwidth minimizes noise while passing signal, optimizing SNR. Improves reception."
Real-World Application
You operate SSB (2.4 kHz bandwidth). You set receiver bandwidth to 2.4 kHz to match. This passes the SSB signal while rejecting noise outside the signal bandwidth, resulting in the best signal-to-noise ratio. Wider bandwidth would let in more noise; narrower bandwidth would cut off the signal. Matching bandwidth optimizes SNR.
Key Concepts
Why Other Options Are Wrong
Option A: Incorrect. Matching bandwidth isn't required by FCC rules - FCC rules don't specify receiver bandwidth matching. FCC rules aren't the reason.
Option B: Incorrect. Matching bandwidth doesn't minimize power consumption - receiver power consumption is relatively constant, not significantly affected by bandwidth. Power consumption isn't the reason.
Option C: Incorrect. Matching bandwidth doesn't improve impedance matching - impedance matching is about antenna/feed line, not receiver bandwidth. Impedance matching isn't the reason.
题目解析
The correct answer is D: It results in the best signal-to-noise ratio. Why it is good to match receiver bandwidth to the bandwidth of the operating mode is that it results in the best signal-to-noise ratio. Matching bandwidth minimizes noise while passing the signal, optimizing SNR. For amateur radio operators, this improves reception. Understanding this helps when operating different modes.
考试技巧
Match receiver bandwidth to mode = results in best signal-to-noise ratio. Think 'M'atch 'B'andwidth = 'M'inimizes 'B'ackground noise. Matching bandwidth minimizes noise while passing signal, optimizing SNR. Not FCC requirement, not power consumption, not impedance matching - just best SNR.
记忆口诀
Match receiver bandwidth to mode = results in best signal-to-noise ratio. Think 'M'atch 'B'andwidth = 'M'inimizes 'B'ackground noise. Matching bandwidth minimizes noise while passing signal, optimizing SNR. Improves reception.
实际应用示例
You operate SSB (2.4 kHz bandwidth). You set receiver bandwidth to 2.4 kHz to match. This passes the SSB signal while rejecting noise outside the signal bandwidth, resulting in the best signal-to-noise ratio. Wider bandwidth would let in more noise; narrower bandwidth would cut off the signal. Matching bandwidth optimizes SNR.
错误选项分析
Option A: Incorrect. Matching bandwidth isn't required by FCC rules - FCC rules don't specify receiver bandwidth matching. FCC rules aren't the reason. Option B: Incorrect. Matching bandwidth doesn't minimize power consumption - receiver power consumption is relatively constant, not significantly affected by bandwidth. Power consumption isn't the reason. Option C: Incorrect. Matching bandwidth doesn't improve impedance matching - impedance matching is about antenna/feed line, not receiver bandwidth. Impedance matching isn't the reason.
知识点
Receiver bandwidth, Mode bandwidth, Signal-to-noise ratio, SNR optimization
Verified Content
Question from official FCC General Class question pool. Explanation reviewed by licensed amateur radio operators.