Deep Dive: G5C10
The correct answer is C: 3.3 millihenries. The inductance of three 10-millihenry inductors connected in parallel is 3.3 millihenries. 1/Ltotal = 1/10 + 1/10 + 1/10 = 3/10 = 0.3. Ltotal = 1/0.3 = 3.33 mH ≈ 3.3 mH. For amateur radio operators, this is a basic parallel inductance calculation. Understanding this helps when analyzing parallel inductors.
Why Other Answers Are Wrong
Option A (0.30 henries): Incorrect. 0.30 henries = 300 mH, which is too high. Answer should be in millihenries, not henries. Unit error. Option B (3.3 henries): Incorrect. 3.3 henries = 3,300 mH, which is way too high. Answer should be in millihenries, not henries. Unit error. Option D (30 millihenries): Incorrect. 30 mH is the sum (series), not parallel. Parallel inductance is less than individual inductors.
Exam Tip
Parallel inductance: 1/L = 1/10 + 1/10 + 1/10 = 0.3, L = 1/0.3 = 3.3 mH. Think 'P'arallel 'L'nductors = 'P'reciprocal sum, then 'R'eciprocal. Use 1/Ltotal = 1/L1 + 1/L2 + 1/L3. Answer in millihenries, not henries. Not 0.30H, not 3.3H, not 30 mH (sum) - just 3.3 mH.
Memory Aid
Parallel inductance: 1/L = 0.3, L = 3.3 mH. Think 'P'arallel 'L'nductors = 'P'reciprocal sum. Use 1/Ltotal = 1/L1 + 1/L2 + 1/L3, then take reciprocal. Answer in millihenries. Standard parallel calculation.
Real-World Example
Three inductors in parallel: 10 mH each. 1/Ltotal = 1/10 + 1/10 + 1/10 = 3/10 = 0.3. Ltotal = 1/0.3 = 3.33 millihenries ≈ 3.3 millihenries. Parallel inductance is less than individual inductors (3.3 < 10).
Source & Coverage
Question Pool: 2023-2027 Question Pool
Subelement: G5C
Reference: 2023-2027 Question Pool · G5 - Electrical Principles
Key Concepts
Verified Content
Question from the official FCC General Class pool. Explanation reviewed by licensed amateur radio operators and mapped to the G5C topic.